A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $8 m$ . If the train's rate of revolution changes from $1/4 Hz$ to $3/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-05-08T05:29:48

The centripetal force changes by $=14.8N$

The centripetal force is

$F=mr omega^2$

mass is $m=3kg$

radius $r=8m$

$Delta omega=(3/8-1/4)*2pi=(1/4pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=3*8*(1/4pi)^2$

$=14.8N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 8 m8 m. If the train's rate of revolution changes from 1/4 Hz1/4 Hz to 3/8 Hz3/8 Hz, by how much will the centripetal force applied by the tracks change by?