A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $2 m$ . If the train's rate of revolution changes from $5/4 Hz$ to $3/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2018-01-15T15:19:01

The change in centrpetal force $=336.8N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(3)kg$

The radius of the track, $r=(2)m$

The frequencies are

$f_1=(5/4)Hz$

$f_2=(3/8)Hz$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=3*2*(2pi*5/4)^2=370.1N$

$F_2=mromega_2^2=mr*(2pif_2)^2=3*2*(2pi*3/8)^2=33.3N$

$DeltaF=F_1-F_2=370.1-33.3=336.8N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 2 m2 m. If the train's rate of revolution changes from 5/4 Hz5/4 Hz to 3/8 Hz3/8 Hz, by how much will the centripetal force applied by the tracks change by?