A model train, with a mass of $3 kg$ , is moving on a circular track with a radius of $2 m$ . If the train's rate of revolution changes from $5/3 Hz$ to $1/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2018-01-23T06:28:23

The change in centripetal force is $=654.3N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(3)kg$

The radius of the track, $r=(2)m$

The frequencies are

$f_1=(5/3)Hz$

$f_2=(1/8)Hz$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=3*2*(2pi*5/3)^2=658.0N$

$F_2=mromega_2^2=mr*(2pif_2)^2=3*2*(2pi*1/8)^2=3.7N$

$DeltaF=F_1-F_2=658-3.7=654.3N$

A model train, with a mass of 3 kg3 kg, is moving on a circular track with a radius of 2 m2 m. If the train's rate of revolution changes from 5/3 Hz5/3 Hz to 1/8 Hz1/8 Hz, by how much will the centripetal force applied by the tracks change by?