A model train with a mass of $4 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $25 cm$ to $14 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-07-23T12:08:27

The change in centripetal force is $=0.41N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=4kg$

The velocity of the train is $v=0.18ms^-1$

The radii of the tracks are

$r_1=0.25m$

and

$r_2=0.14m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=4*0.18^2/0.25=0.518N$

$||F_2||=4*0.18^2/0.14=0.926N$

$DeltaF=|F_1-F_2|=0.926-0.518=0.41N$

A model train with a mass of 4 kg4 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 25 cm25 cm to 14 cm14 cm, by how much must the centripetal force applied by the tracks change?