A model train with a mass of $4 kg$ is moving along a track at $21 (cm)/s$ . If the curvature of the track changes from a radius of $42 cm$ to $140 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-01-25T12:47:20

The change in centripetal force is $=0.294N$

The centripetal force is

$F=(mv^2)/r$

The mass is of the train $m=4kg$

The velocity of the train is $v=0.21ms^-1$

The radii are

$r_1=0.42m$

and

$r_2=1.40m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=4*0.21^2/0.42=0.42N$

$F_2=4*0.21^2/1.40=0.126N$

$DeltaF=F_1-F_2=0.42-0.126=0.294N$

A model train with a mass of 4 kg4 kg is moving along a track at 21 (cm)/s21 (cm)/s. If the curvature of the track changes from a radius of 42 cm42 cm to 140 cm140 cm, by how much must the centripetal force applied by the tracks change?