A model train with a mass of $4 kg$ is moving along a track at $21 (cm)/s$ . If the curvature of the track changes from a radius of $84 cm$ to $140 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-08-29T10:27:06

$8400 dy n e or 0.084N$

$m=4000g$

$v=21cm*s^(-1)$

$R_1=84cm$

$F_(c(1)) =( mv^2)/R_1$

$=(4000*21^2)/84$

$=21000" dyne"$

$R_2=140cm$

$F_(c(2)) =( mv^2)/R_2$

$=(4000*21^2)/140$

$=12600" dyne"$

Change in $F_c = F_(c(1)) - F_(c(2))$

$=21000-12600 " dyne" =8400" dyne" =0.084 N$

A model train with a mass of 4 kg4 kg is moving along a track at 21 (cm)/s21 (cm)/s. If the curvature of the track changes from a radius of 84 cm84 cm to 140 cm140 cm, by how much must the centripetal force applied by the tracks change?