A model train with a mass of $4 kg$ is moving along a track at $9 (cm)/s$ . If the curvature of the track changes from a radius of $180 cm$ to $63 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-14T12:50:25

The centripetal force changes by $0.028N$

The centripetal force is

$F=(mv^2)/r$

The change in centripetal force is

$DeltaF=(mv^2)/(Delta r)$

So,

$DeltaF=(4*0.09^2)/(1.8-0.63)=0.0324/1.17N$

$=0.028N$

A model train with a mass of 4 kg4 kg is moving along a track at 9 (cm)/s9 (cm)/s. If the curvature of the track changes from a radius of 180 cm180 cm to 63 cm63 cm, by how much must the centripetal force applied by the tracks change?