A model train with a mass of $4 kg$ is moving along a track at $9 (cm)/s$ . If the curvature of the track changes from a radius of $180 cm$ to $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-07-29T08:43:54

The change in centripetal force is $=0.177N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=(4)kg$

speed, $v=(0.09)ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=4*0.09^2/1.8=0.018N$

$F_2=mv^2/r_2=4*0.09^2/0.24=0.135N$

$DeltaF=0.135-0.018=0.177N$

A model train with a mass of 4 kg4 kg is moving along a track at 9 (cm)/s9 (cm)/s. If the curvature of the track changes from a radius of 180 cm180 cm to 24 cm24 cm, by how much must the centripetal force applied by the tracks change?