A model train, with a mass of $4 k g$ $4 kg$ , is moving on a circular track with a radius of $5 m$ $5 m$ . If the train's rate of revolution changes from $\frac{1}{9} H z$ $1/9 Hz$ to $\frac{1}{5} H z$ $1/5 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-05-29T18:23:55

The centripetal force changes by $= 6.24 N$ $=6.24N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

mass is $m = 4 k g$ $m=4kg$

radius $r = 5 m$ $r=5m$

$Delta omega=(1/5-1/9)*2pi=(8/45pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=4*5*(8/45pi)^2$

$=6.24N$

A model train, with a mass of 4 kg4kg4 kg, is moving on a circular track with a radius of 5 m5m5 m. If the train's rate of revolution changes from 1/9 Hz19Hz1/9 Hz to 1/5 Hz15Hz1/5 Hz, by how much will the centripetal force applied by the tracks change by?