A model train, with a mass of $4 k g$ $4 kg$ , is moving on a circular track with a radius of $7 m$ $7 m$ . If the train's rate of revolution changes from $\frac{1}{12} H z$ $1/12 Hz$ to $\frac{1}{3} H z$ $1/3 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-08-23T13:20:13

The change in centripetal force is $= 69.1 N$ $=69.1N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

The mass is $m = 4 k g$ $m=4kg$

The radius $r = 7 m$ $r=7m$

The change in angular velocity is

$Delta omega=(1/3-1/12)*2pi=(1/2pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=4*7*(1/2pi)^2$

$=69.1N$

A model train, with a mass of 4 kg4kg4 kg, is moving on a circular track with a radius of 7 m7m7 m. If the train's rate of revolution changes from 1/12 Hz112Hz1/12 Hz to 1/3 Hz13Hz1/3 Hz, by how much will the centripetal force applied by the tracks change by?