A model train with a mass of $5 k g$ $5 kg$ is moving along a track at $14 \frac{c m}{s}$ $14 (cm)/s$ . If the curvature of the track changes from a radius of $7 c m$ $7 cm$ to $24 c m$ $24 cm$ , by how much must the centripetal force applied by the tracks change?

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A model train with a mass of $5 k g$ $5 kg$ is moving along a track at $14 \frac{c m}{s}$ $14 (cm)/s$ . If the curvature of the track changes from a radius of $7 c m$ $7 cm$ to $24 c m$ $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2016-05-07T07:34:52

A change of $Delta F=119/120=0.9916666" "$ Newton

Explanation:

Given data: $v=14" "$ cm/second $=0.14" "$ meter/second
$m=5" "$ kilogram
$r_1=7" "$ centimeter $=.07" "$ meter
$r_2=24" "$ centimeter $=0.24" "$ meter

Centripetal Force formula

$F_1=(mv^2)/r_1=(5*(.14)^2)/(.07)=7/5" "$ Newtons

$F_2=(mv^2)/r_2=(5*(.14)^2)/(.24)=49/120" "$ Newtons

$F_1-F_2=Delta F=119/120=0.9916666" "$ Newton

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A model train with a mass of $5 k g$ $5 kg$ is moving along a track at $14 \frac{c m}{s}$ $14 (cm)/s$ . If the curvature of the track changes from a radius of $7 c m$ $7 cm$ to $24 c m$ $24 cm$ , by how much must the centripetal force applied by the tracks change?

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Explanation:

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A model train with a mass of 5 kg5kg5 kg is moving along a track at 14 (cm)/s14cms14 (cm)/s. If the curvature of the track changes from a radius of 7 cm7cm7 cm to 24 cm24cm24 cm, by how much must the centripetal force applied by the tracks change?

1 Answer

Explanation:

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A model train with a mass of $5 k g$ $5 kg$ is moving along a track at $14 \frac{c m}{s}$ $14 (cm)/s$ . If the curvature of the track changes from a radius of $7 c m$ $7 cm$ to $24 c m$ $24 cm$ , by how much must the centripetal force applied by the tracks change?