A model train with a mass of $5 kg$ is moving along a track at $16 (cm)/s$ . If the curvature of the track changes from a radius of $88 cm$ to $28 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-02-09T03:52:40

The $DeltaF=0.3117$

Assuming constant velocity and mass.

$DeltaF=F_2-F_1$
The change in force is equivalent to the force being applied currently subtracted from the force that will be applied.

Physics is always in Kilograms, Meters, and Seconds . So convert.

$F_"Centripital"=[(mass)*(velocity)^2]/(radius)$

Use the equation to plug into our formula for $DeltaF$

$DeltaF=[(m_2)*(v_2)^2]/(r_2)-[(m_1)*(v_1)^2]/(r_1)$

$DeltaF=[(5)*(0.16)^2]/(0.28)-[(5)*(0.16)^2]/(0.88)$

A model train with a mass of 5 kg5 kg is moving along a track at 16 (cm)/s16 (cm)/s. If the curvature of the track changes from a radius of 88 cm88 cm to 28 cm28 cm, by how much must the centripetal force applied by the tracks change?