A model train with a mass of $5 kg$ is moving along a track at $4 (cm)/s$ . If the curvature of the track changes from a radius of $16 cm$ to $2 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2016-04-02T11:34:19

0.35N

We have that:

The centripetal force is given by:

$F = (mv^2)/r$

Thus we can work out the change in centripetal force:

$DeltaF = F_2-F_1=(mv^2)/r_2 -( mv^2)/r_1$

$=((5)(0.04)^2)/0.02-((5)(0.04)^2)/0.16=0.35N$

A model train with a mass of 5 kg5 kg is moving along a track at 4 (cm)/s4 (cm)/s. If the curvature of the track changes from a radius of 16 cm16 cm to 2 cm2 cm, by how much must the centripetal force applied by the tracks change?