A model train, with a mass of $5 kg$ , is moving on a circular track with a radius of $3 m$ . If the train's rate of revolution changes from $1/2 Hz$ to $2/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

Question

1469 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-16T15:20:05

The change in centripetal force is $=111.03N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(5)kg$

The radius of the track, $r=(3)m$

The frequencies are

$f_1=(1/2)Hz$

$f_2=(2/8)Hz$

The angular velocity is $omega=2pif$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=5*3*(2pi*1/2)^2=148.04N$

$F_2=mromega_2^2=mr*(2pif_2)^2=5*3*(2pi*1/4)^2=37.01N$

$DeltaF=F_1-F_2=148.04-37.01=111.03N$

A model train, with a mass of 5 kg5 kg, is moving on a circular track with a radius of 3 m3 m. If the train's rate of revolution changes from 1/2 Hz1/2 Hz to 2/8 Hz2/8 Hz, by how much will the centripetal force applied by the tracks change by?