A model train, with a mass of $5 kg$ , is moving on a circular track with a radius of $3 m$ . If the train's rate of revolution changes from $1/4 Hz$ to $3/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-03-23T13:16:39

The centripetal force change by $=9.52N$

The centripetal force is

$F=mr omega^2$

mass is $m=5kg$

radius $r=3m$

$Delta omega=(3/8-1/4)*2pi=(1/4pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=5*3*(1/4pi)^2$

$=9.25N$

A model train, with a mass of 5 kg5 kg, is moving on a circular track with a radius of 3 m3 m. If the train's rate of revolution changes from 1/4 Hz1/4 Hz to 3/8 Hz3/8 Hz, by how much will the centripetal force applied by the tracks change by?