A model train, with a mass of $5 kg$ , is moving on a circular track with a radius of $3 m$ . If the train's rate of revolution changes from $1/3 Hz$ to $3/8 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-06-12T13:25:16

The change in centripetal force is $=1.03N$

The centripetal force is

$F=mr omega^2$

mass is $m=5kg$

radius $r=3m$

$Delta omega=(3/8-1/3)*2pi=(1/12pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=5*3*(1/12pi)^2$

$=1.03N$

A model train, with a mass of 5 kg5 kg, is moving on a circular track with a radius of 3 m3 m. If the train's rate of revolution changes from 1/3 Hz1/3 Hz to 3/8 Hz3/8 Hz, by how much will the centripetal force applied by the tracks change by?