A model train, with a mass of $5 k g$ $5 kg$ , is moving on a circular track with a radius of $9 m$ $9 m$ . If the train's rate of revolution changes from $5 H z$ $5 Hz$ to $9 H z$ $9 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-07-03T11:59:13

The centripetal force changes by $= 28.424 k N$ $=28.424kN$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

The mass is $m = 5 k g$ $m=5kg$

The radius $r = 9 m$ $r=9m$

The change in angular velocity is

$Delta omega=(9-5)*2pi=(8pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=5*9*(8pi)^2$

$=28424N$

A model train, with a mass of 5 kg5kg5 kg, is moving on a circular track with a radius of 9 m9m9 m. If the train's rate of revolution changes from 5 Hz5Hz5 Hz to 9 Hz9Hz9 Hz, by how much will the centripetal force applied by the tracks change by?