A model train with a mass of $6 kg$ is moving along a track at $12 (cm)/s$ . If the curvature of the track changes from a radius of $3 cm$ to $15 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-07T13:29:13

The change in centripetal force is $=2.304N$

The centripetal force is

$F=(mv^2)/r$

$m=mass=6kg$

$v=0.12ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=6*0.12^2/0.03=2.88N$

$F_2=6*0.12^2/0.15=0.576N$

$DeltaF=2.88-0.576=2.304N$

A model train with a mass of 6 kg6 kg is moving along a track at 12 (cm)/s12 (cm)/s. If the curvature of the track changes from a radius of 3 cm3 cm to 15 cm15 cm, by how much must the centripetal force applied by the tracks change?