A model train, with a mass of $6 k g$ $6 kg$ , is moving on a circular track with a radius of $7 m$ $7 m$ . If the train's rate of revolution changes from $4 H z$ $4 Hz$ to $2 H z$ $2 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-12-31T06:43:53

The change in centripetal force is $= 19897.1 N$ $=19897.1N$

The centripetal force is

$F = \frac{m v^{2}}{r} = m r ω^{2} N$ $F=(mv^2)/r=mromega^2N$

The mass of the train, $m = (6) k g$ $m=(6)kg$

The radius of the track, $r = 7 m$ $r=7m$

The frequencies are

$f_{1} = 4 H z$ $f_1=4Hz$

$f_{2} = 2 H z$ $f_2=2Hz$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=6*7*(2pi*4)^2=26529.5N$

$F_2=mromega_2^2=mr*(2pif_2)^2=6*7*(2pi*2)^2=6632.4N$

$DeltaF=F_1-F_2=26529.5-6632.4=19897.1N$

A model train, with a mass of 6 kg6kg6 kg, is moving on a circular track with a radius of 7 m7m7 m. If the train's rate of revolution changes from 4 Hz4Hz4 Hz to 2 Hz2Hz2 Hz, by how much will the centripetal force applied by the tracks change by?