A model train with a mass of $7 k g$ $7 kg$ is moving along a track at $12 \frac{c m}{s}$ $12 (cm)/s$ . If the curvature of the track changes from a radius of $24 c m$ $24 cm$ to $36 c m$ $36 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-04-05T10:04:24

The centripetal force changes by $= 0.14 N$ $=0.14N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

mass, $m = 7 k g$ $m=7kg$

speed, $v = 0.12 m s^{- 1}$ $v=0.12ms^-1$

radius, $= r$ $=r$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=7*0.12^2/0.24=0.42N$

$F_2=7*0.02^2/0.36=0.28N$

$DeltaF=F_1-F_2=0.42-0.28=0.14N$

A model train with a mass of 7 kg7kg7 kg is moving along a track at 12 (cm)/s12cms12 (cm)/s. If the curvature of the track changes from a radius of 24 cm24cm24 cm to 36 cm36cm36 cm, by how much must the centripetal force applied by the tracks change?