A model train with a mass of $7 k g$ $7 kg$ is moving along a track at $15 \frac{c m}{s}$ $15 (cm)/s$ . If the curvature of the track changes from a radius of $32 c m$ $32 cm$ to $45 c m$ $45 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-12-13T08:04:18

The change in centripetal force is $= 0.41 N$ $=0.41N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass is of the train $m = 7 k g$ $m=7kg$

The velocity is $v = 0.15 m s^{- 1}$ $v=0.15ms^-1$

The radii are

$r_{1} = 0.32 m$ $r_1=0.32m$

and

$r_{2} = 0.45 m$ $r_2=0.45m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=7*0.15^2/0.32=0.49N$

$F_2=7*0.15^2/0.45=0.35N$

$DeltaF=0.49-0.35=0.14N$

A model train with a mass of 7 kg7kg7 kg is moving along a track at 15 (cm)/s15cms15 (cm)/s. If the curvature of the track changes from a radius of 32 cm32cm32 cm to 45 cm45cm45 cm, by how much must the centripetal force applied by the tracks change?