A model train, with a mass of $7 kg$ , is moving on a circular track with a radius of $6 m$ . If the train's rate of revolution changes from $1/3 Hz$ to $2/7 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-12-06T06:26:32

The change in centripetal force is $=45N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(7)kg$

The radius of the track, $r=6m$

The frequencies are

$f_1=1/3=0.33Hz$

$f_2=2/7=0.286Hz$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=7*6*(2pi*0.33)^2=180.6N$

$F_2=mromega_2^2=mr*(2pif_2)^2=7*6*(2pi*0.286)^2=135.6N$

$DeltaF=F_1-F_2=180.6-135.6=45N$

A model train, with a mass of 7 kg7 kg, is moving on a circular track with a radius of 6 m6 m. If the train's rate of revolution changes from 1/3 Hz1/3 Hz to 2/7 Hz2/7 Hz, by how much will the centripetal force applied by the tracks change by?