A model train, with a mass of 7 kg7kg, is moving on a circular track with a radius of 6 m6m. If the train's rate of revolution changes from 1/2 Hz12Hz to 2/7 Hz27Hz, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 16, 2017

The centripetal force will change by 19.03N19.03N

Explanation:

The centripetal force is

F=mr omega^2F=mrω2

The variation in centripetal force is

DeltaF=mr(Delta omega)^2

=7*6*((1/2-2/7)2pi)^2

=42*9/14^2*pi^2

=19.03N