A model train with a mass of $8 k g$ $8 kg$ is moving along a track at $15 \frac{c m}{s}$ $15 (cm)/s$ . If the curvature of the track changes from a radius of $45 c m$ $45 cm$ to $225 c m$ $225 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-12T14:01:34

The centripetal force is $0.1 N$ $0.1N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The variation in centripetal force is

$DeltaF=(mv^2)/(Delta r)$

$=(8*(0.15)^2)/(2.25-0.45)$

$=(8*0.0225)/1.8$

$=0.1N$

A model train with a mass of 8 kg8kg8 kg is moving along a track at 15 (cm)/s15cms15 (cm)/s. If the curvature of the track changes from a radius of 45 cm45cm45 cm to 225 cm225cm225 cm, by how much must the centripetal force applied by the tracks change?