A model train with a mass of $8 kg$ is moving along a track at $16 (cm)/s$ . If the curvature of the track changes from a radius of $21 cm$ to $120 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-01T10:34:49

The change in centripetal force is $=0.71N$

The centripetal force is

$F=(mv^2)/r$

$m=mass=1kg$

$v=0.16ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=8*0.16^2/0.21=0.98N$

$F_2=8*0.16^2/1.2=0.17N$

$DeltaF=0.88-0.17=0.71N$

A model train with a mass of 8 kg8 kg is moving along a track at 16 (cm)/s16 (cm)/s. If the curvature of the track changes from a radius of 21 cm21 cm to 120 cm120 cm, by how much must the centripetal force applied by the tracks change?