A model train with a mass of 8 kg is moving along a track at 9 (cm)/s. If the curvature of the track changes from a radius of 21 cm to 72 cm, by how much must the centripetal force applied by the tracks change?

1 Answer

Change in centripetal force
Delta F=21,857.14286" "Dynes

Explanation:

Given data:
m=8 " "kg
v=9" ""cm/sec"

r_1=21" ""cm"
r_2=72" ""cm"

For Centripetal Force

F=(m*v^2)/r

F_1=(m*v^2)/r_1=(8000*9^2)/21=30857.14286

F_2=(m*v^2)/r_2=(8000*9^2)/72=9000

Delta F=F_1-F_2=21,857.14286" "Dynes

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