A model train, with a mass of 88 kgkg, is moving on a circular track with a radius of 11 mm. If the train's kinetic energy changes from 3232 JJ to 00 JJ, by how much will the centripetal force applied by the tracks change?

1 Answer
Jun 24, 2016

The centripetal force is given by F=(mv^2)/rF=mv2r, and we can calculate the change in vv from the change in the kinetic energy, E_k=1/2mv^2Ek=12mv2. The change in the centripetal force acting is -6464 NN.

Explanation:

The kinetic energy is given by E_k=1/2mv^2Ek=12mv2, and we can rearrange to make vv the subject:

v=sqrt((2E_k)/m)v=2Ekm

The final kinetic energy is zero and therefore the final velocity is zero.

We can use the mass, radius and initial kinetic energy to calculate the initial velocity:

v=sqrt((2E_k)/m)=sqrt((2*32)/8) = sqrt (64/8) =sqrt8~~2.8v=2Ekm=2328=648=82.8 ms^-1ms1

Since the final velocity is zero, the final centripetal force will be zero. The initial centripetal force will be:

F=(mv^2)/r=(8*2.8^2)/1=64F=mv2r=82.821=64 NN.

Since the final centripetal force is 00 NN, the change in the centripetal force is:

final - initial = 0-64=-64064=64 NN