A model train, with a mass of $8 kg$ , is moving on a circular track with a radius of $1 m$ . If the train's rate of revolution changes from $3/5 Hz$ to $5/6 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2018-05-14T19:06:57

The change in centripetal force is $=105.6N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(8)kg$

The radius of the track, $r=(1)m$

The frequencies are

$f_1=(3/5)Hz$

$f_2=(5/6)Hz$

The angular velocity is $omega=2pif$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=8*1*(2pi*3/5)^2=113.7N$

$F_2=mromega_2^2=mr*(2pif_2)^2=8*1*(2pi*5/6)^2=219.3N$

$DeltaF=|F_2-F_1|=219.3-113.7=105.6N$

A model train, with a mass of 8 kg8 kg, is moving on a circular track with a radius of 1 m1 m. If the train's rate of revolution changes from 3/5 Hz3/5 Hz to 5/6 Hz5/6 Hz, by how much will the centripetal force applied by the tracks change by?