A model train, with a mass of $8 k g$ $8 kg$ , is moving on a circular track with a radius of $1 m$ $1 m$ . If the train's rate of revolution changes from $\frac{3}{5} H z$ $3/5 Hz$ to $\frac{5}{4} H z$ $5/4 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-02-24T13:41:23

The change in centripetal force is $= 133.4 N$ $=133.4N$

The centripetal force is

$F = m r ω^{2}$ $F=mr omega^2$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=8*1*((5/4-3/5)2pi)^2$

$=8*13^2/100*pi^2$

$=133.4N$

A model train, with a mass of 8 kg8kg8 kg, is moving on a circular track with a radius of 1 m1m1 m. If the train's rate of revolution changes from 3/5 Hz35Hz3/5 Hz to 5/4 Hz54Hz5/4 Hz, by how much will the centripetal force applied by the tracks change by?