A model train, with a mass of $8 kg$ , is moving on a circular track with a radius of $1 m$ . If the train's rate of revolution changes from $5/8 Hz$ to $1/4 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2017-05-12T05:43:50

The change in centripetal force is $=11.1N$

The centripetal force is

$F=mr omega^2$

mass is $m=8kg$

radius $r=1m$

$Delta omega=(5/8-1/4)*2pi=(3/8pi)rads^-1$

The variation in centripetal force is

$DeltaF=mr(Delta omega)^2$

$=8*1*(3/8pi)^2$

$=11.1N$

A model train, with a mass of 8 kg8 kg, is moving on a circular track with a radius of 1 m1 m. If the train's rate of revolution changes from 5/8 Hz5/8 Hz to 1/4 Hz1/4 Hz, by how much will the centripetal force applied by the tracks change by?