A model train, with a mass of $8 kg$ , is moving on a circular track with a radius of $6 m$ . If the train's rate of revolution changes from $5/3 Hz$ to $1/4 Hz$ , by how much will the centripetal force applied by the tracks change by?

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Answer 1 · 2018-05-01T06:44:51

The change in centripetal force is $=5145.35N$

The centripetal force is

$F=(mv^2)/r=mromega^2N$

The mass of the train, $m=(8)kg$

The radius of the track, $r=(6)m$

The frequencies are

$f_1=(5/3)Hz$

$f_2=(1/4)Hz$

The angular velocity is $omega=2pif$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mromega_1^2=mr*(2pif_1)^2=8*6*(2pi*5/3)^2=5263.79N$

$F_2=mromega_2^2=mr*(2pif_2)^2=8*6*(2pi*1/4)^2=118.44N$

$DeltaF=F_2-F_1=5263.79-118.44=5145.35N$

A model train, with a mass of 8 kg8 kg, is moving on a circular track with a radius of 6 m6 m. If the train's rate of revolution changes from 5/3 Hz5/3 Hz to 1/4 Hz1/4 Hz, by how much will the centripetal force applied by the tracks change by?