A model train with a mass of $9 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $32 cm$ to $42 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-02T07:40:59

The change in centripetal force is $=0.22N$

The centripetal force is

$F=(mv^2)/r$

$m=mass=9kg$

$v=0.18ms^-1$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=9*0.18^2/0.32=0.91N$

$F_2=9*0.18^2/0.42=0.69N$

$DeltaF=0.91-0.69=0.22N$

A model train with a mass of 9 kg9 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 32 cm32 cm to 42 cm42 cm, by how much must the centripetal force applied by the tracks change?