A model train with a mass of $9 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $66 cm$ to $42 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-06-25T05:44:53

The centripetal force changes by $=0.25N$

The centripetal force is

$F=(mv^2)/r$

mass, $m=9kg$

speed, $v=0.18ms^-1$

radius, $=(r) m$

The variation in centripetal force is

$DeltaF=F_2-F_1$

$F_1=mv^2/r_1=9*0.18^2/0.66=0.44N$

$F_2=mv^2/r_2=9*0.18^2/0.42=0.69N$

$DeltaF=0.69-0.44=0.25N$

A model train with a mass of 9 kg9 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 66 cm66 cm to 42 cm42 cm, by how much must the centripetal force applied by the tracks change?