A model train with a mass of $9 kg$ is moving along a track at $18 (cm)/s$ . If the curvature of the track changes from a radius of $36 cm$ to $42 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-08-01T14:03:42

The change in centripetal force is $=0.12N$

The centripetal force is

$vecF_C=(mv^2)/r*vecr$

The mass is of the train $m=9kg$

The velocity of the train is $v=0.18ms^-1$

The radii of the tracks are

$r_1=0.36m$

and

$r_2=0.42m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$||F_1||=9*0.18^2/0.36=0.81N$

$||F_2||=9*0.18^2/0.42=0.69N$

$DeltaF=|F_1-F_2|=0.81-0.69=0.12N$

A model train with a mass of 9 kg9 kg is moving along a track at 18 (cm)/s18 (cm)/s. If the curvature of the track changes from a radius of 36 cm36 cm to 42 cm42 cm, by how much must the centripetal force applied by the tracks change?