A model train with a mass of $9 k g$ $9 kg$ is moving along a track at $18 \frac{c m}{s}$ $18 (cm)/s$ . If the curvature of the track changes from a radius of $36 c m$ $36 cm$ to $35 c m$ $35 cm$ , by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2018-01-24T06:36:53

The change in centripetal force is $= 0.023 N$ $=0.023N$

The centripetal force is

$F = \frac{m v^{2}}{r}$ $F=(mv^2)/r$

The mass is of the train $m = 9 k g$ $m=9kg$

The velocity of the train is $v = 0.18 m s^{- 1}$ $v=0.18ms^-1$

The radii are

$r_{1} = 0.36 m$ $r_1=0.36m$

and

$r_{2} = 0.35 m$ $r_2=0.35m$

The variation in the centripetal force is

$DeltaF=F_2-F_1$

The centripetal forces are

$F_1=9*0.18^2/0.36=0.833N$

$F_2=9*0.18^2/0.35=0.81N$

$DeltaF=F_1-F_2=0.833-0.81=0.023N$

A model train with a mass of 9 kg9kg9 kg is moving along a track at 18 (cm)/s18cms18 (cm)/s. If the curvature of the track changes from a radius of 36 cm36cm36 cm to 35 cm35cm35 cm, by how much must the centripetal force applied by the tracks change?