A neutralization reaction between $K O H (a q)$ $KOH(aq)$ and $H_{2} S O_{4} (a q)$ $H_2SO_4(aq)$ would give which two products?

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Answer 1 · 2017-03-11T20:58:00

$Water and potassium sulfate.........$ $"Water and potassium sulfate........."$

This is an acid base reaction, where 1 equivalent of the diprotic sulfuric acid reacts with 2 equiv of potassium hydroxide:

$H_{2} S O_{4} (a q) + 2 K O H (a q) \to K_{2} S O_{4} (a q) + 2 H_{2} O (l)$ $H_2SO_4(aq) + 2KOH(aq) rarr K_2SO_4(aq) + 2H_2O(l)$

Of course, in aqueous solution, $K_{2} S O_{4} (a q)$ $K_2SO_4(aq)$ is $2 \times K^{+}$ $2xxK^+$ , and $S O_{4}^{2 -}$ $SO_4^(2-)$ ..........

A neutralization reaction between KOH(aq)KOH(aq) and H2SO4(aq)H_2SO_4(aq) would give which two products?