A particle starts to move in a circle of radius 1 m with an angular acceleration 1 rad/s^2. If the mass of the particle is 2 kg and it started from rest and moved on a horizontal surface, what is the total force acting on it at t=2 seconds?
I'm really not sure if this question is even correct because I can't even understand it so please let me know if it is wrong. Answer : #sqrt17 N#
I'm really not sure if this question is even correct because I can't even understand it so please let me know if it is wrong. Answer :
1 Answer
I got double the posted answer.
Explanation:
Angular velocity after
#omega_f=omega_i+alphat#
#omega_f=0+1xx2=2\ rad *s^-1#
Radial acceleration
#a_r=Romega_f^2#
#a_r=(1)(2)^2=4\ ms^-2# ......(1)
Now the tangential acceleration
#a_t=Ralpha#
#a_t=1(1)=1\ ms^-2# ......(2)
Total acceleration
#veca_("total")=veca_r+veca_t#
#=>|veca_("total")|=sqrt(a_r^2+a_t^2)#
Inserting calculated values we get
#|veca_("total")|=sqrt(4^2+1^2)#
#|veca_("total")|=sqrt17\ ms^-2#