A pinball bangs against a bumper, giving the ball a speed of 52 cm/s. If the ball has a mass of 50.0 g, what is the ball's kinetic energy in joules?

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A pinball bangs against a bumper, giving the ball a speed of 52 cm/s. If the ball has a mass of 50.0 g, what is the ball's kinetic energy in joules?

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Answer 1 · 2016-02-03T17:04:09

I found: $K = 6.76 \times 10^{- 3} J$ $K=6.76xx10^-3J$

Explanation:

We need first to change into $\frac{m}{s}$ $m/s$ and $k g$ $kg$ to get:
$52 \frac{c m}{s} = \frac{52}{100} \frac{m}{s} = 0.52 \frac{m}{s}$ $52(cm)/s=52/100m/s=0.52m/s$
and:
$50 g = \frac{50}{1000} k g = 0.05 k g$ $50g=50/1000kg=0.05kg$
Kinrtic Energy will be:
$K = \frac{1}{2} m v^{2} = \frac{1}{2} (0.05) {(0.52)}^{2} = 6.76 \times 10^{- 3} J$ $K=1/2mv^2=1/2(0.05)(0.52)^2=6.76xx10^-3J$

Answer 2 · 2016-02-03T17:05:47

$6.76 \times 10^{- 3} j$ $6.76xx10^(-3)j$

Explanation:

we know that,

$E_{K} = \frac{1}{2} m v^{2}$ $E_K=1/2mv^2$

here,
$m = 50 g m = 0.05 k g$ $m=50gm=0.05kg$
$v = 52 \frac{c m}{s} = 0.52 \frac{m}{s}$ $v=52(cm)/s=0.52m/s$

so,
$E_{K} = \frac{1}{2} \cdot 0.05 \cdot {(0.52)}^{2}$ $E_K=1/2*0.05*(0.52)^2$
$= 6.76 \times 10^{- 3} j$ $=6.76xx10^(-3)j$

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A pinball bangs against a bumper, giving the ball a speed of 52 cm/s. If the ball has a mass of 50.0 g, what is the ball's kinetic energy in joules?

2 Answers

Explanation:

Explanation:

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