A projectile is shot at a velocity of # 1 m/s# and an angle of #pi/4 #. What is the projectile's peak height?
1 Answer
Mar 10, 2018
If the projectile is shot at a velocity of
The maximum height will occur when the vertical component of velocity equals
We now need to find a kinematic equation that will make sense for this problem.
#v_y^2 = v_(y_0)^2 + 2a_y(Deltay)#
We will be solving for
#0 = 1/2 + 2(-9.8)Deltay#
#Delta y = 0.026# meters, or#2.6# cm.
Hopefully this helps!