Question

A projectile is shot at an angle of `(5pi)/12` and a velocity of `2 m/s`. How far away will the projectile land?

Answer 1

`~~0.2m`

Explanation:

vertcal component of the velocity of projection `usinalpha=2*sin(5pi/12)=2*0.97=1.94ms^-1`
if t be the time of flight
then
`0=usinalphat-1/2g*t^2`
`t=2usinalpha/g=2*1.94/10=0.388s`
The horizontal displacement of the projectile `ucosalphat=2*cos(5pi/12)*0.388~~0.2m`