Question

A projectile is shot at an angle of `(5pi)/12` and a velocity of `72 m/s`. How far away will the projectile land?

Answer 1

see below

Explanation:

Apply the formula for horizontal range with `theta=(5pi)/12` and `v_0=72m/s`

Horizontal range, `R=(v_0^2sin(2theta))/g`

`=>R=((72)^2*sin(2*(5pi)/12))/9.8=264.49` `m`

Hence, it will land at a distance of `264.49` `m` from the point of projection.