A projectile is shot at an angle of $pi/12$ and a velocity of $24 m/s$ . How far away will the projectile land?

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Answer 1 · 2017-07-10T09:43:28

The distance is $=29.4m$

Resolving in the vertical direction $uarr^+$

We apply the equation of motion

$s=ut+1/2at^2$

$s=0$

The initial velocity is $u=u_0sintheta=24sin(1/12pi)$

The acceleratio is $a=-g$

Therefore,

$24sin(1/12pi)*t-1/2g t^2 =0$

$t=0$ which is the starting time and the time to land is

$t=2*24sin(1/12pi)/g$

$=1.27s$

Resolving in the horizontal direction $rarr^+$

We apply the equation of motion

$d=ucostheta*t$

$d=24cos(1/12pi)*1.27=29.4m$

A projectile is shot at an angle of pi/12 pi/12 and a velocity of 24 m/s 24 m/s. How far away will the projectile land?