A projectile is shot at an angle of #pi/12 # and a velocity of # 24 m/s#. How far away will the projectile land?

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Answer 1 · 2017-07-10T09:43:28

The distance is #=29.4m#

Resolving in the vertical direction #uarr^+#

We apply the equation of motion

#s=ut+1/2at^2#

#s=0#

The initial velocity is #u=u_0sintheta=24sin(1/12pi)#

The acceleratio is #a=-g#

Therefore,

#24sin(1/12pi)*t-1/2g t^2 =0#

#t=0# which is the starting time and the time to land is

#t=2*24sin(1/12pi)/g#

#=1.27s#

Resolving in the horizontal direction #rarr^+#

We apply the equation of motion

#d=ucostheta*t#

#d=24cos(1/12pi)*1.27=29.4m#