Question

A projectile is shot at an angle of `pi/12` and a velocity of `46 m/s`. How far away will the projectile land?

Answer 1

The projectile will fall `107.8m` far

Explanation:

Consider the two equation of speed
`s(x)=vt` with `v=cos15°`
`s(y)=vt-1/2at^2` with `v=sin15°`
Find the time when `s(y)=0`, so `t(v-1/2at)=0`
`t(fall)=2v/g=2.43s` and use this value in the horizontal equation
`s(t)=(46cos15°)*2.43=107.8m`