Question

A projectile is shot at an angle of `pi/3` and a velocity of `24 m/s`. How far away will the projectile land?

Answer 1

`x_m=50,8478 m`

Explanation:

`theta=cancel(pi)/3*180/cancel(pi)=60^o`
`v_(ix)":x component of initial velocity"`
`t_(et):"elapsed time"`
`x_m=v_(ix)* t_(et)`
`v_(ix)=v_i*cos theta`
`v_(ix)=24* 0.5=12 m/s`
`t_(et)=(2*v_i*sin theta)/g`
`t_(et)=(2*24*0,866)/(9,81)`
`t_(et)=4,2373088685 s`
`x_m=12*4,2373088685`
`x_m=50,8478 m`