Question

A projectile is shot at an angle of `pi/6` and a velocity of `24 m/s`. How far away will the projectile land?

Answer 1

The projectile will land `50.9m` far.

Explanation:

Find the time t when the projectile lands, with the vertical equation `s(y)=vt-1/2at^2=0`; `t=2v/g` with `v=vsin30°`
So `t(fall)=2.45m`
Use this value in the horizontal equation to find the lenght of the motion:
`s(x)=vt` with `v=vcos30°` and `t=t(fall)`
`s(t)=(vcos30°)*(t(fall))=50.9m`