Question

A projectile is shot at an angle of `pi/6` and a velocity of `8 m/s`. How far away will the projectile land?

Answer 1

The projectile will land `5.68m` far.

Explanation:

Find the time when the projectile lands with the vertical equation `vt-1/2at^2=0` so `t(v-1/2at)=0` `t(fall)=2v/g=(2vsin30°)/g=0.82s`
We use this value in the horizontal equation `s(x)=v*t(fall)`
So `s=vcos30°*t(fall)=5.68m`