A projectile is shot at an angle of #pi/8 # and a velocity of # 8 m/s#. How far away will the projectile land?

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Answer 1 · 2017-05-25T08:05:26

Range = #8.96 x 10 ^ -4# m

My own work (Mert METİN)

Answer 2 · 2017-05-25T09:27:47

#"the x-range of projectile is 4.61 m"#

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#"the x-range of the projectile can be calculated using formula below."#

#x_m=(v_i^2*sin(2alpha))/g#

#"where ; "#
#v_i=8 m/s#
#g=9.81" " m.s^(-1)#

#alpha=pi/8#

#2*alpha=pi/4" , "sin(pi/4)=0.707#

#x_m=(8^2*0.707)/(9.81)=(64*0.707)/(9.81)#

#x_m=4.61 m#