A projectile is shot from the ground at an angle of #pi/12 # and a speed of #7 /18 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
3 Answers
distance from starting point is
Explanation:
Range,
When the particle reaches its maximum height, the distance from starting point will be
[Take
Explanation:
We're asked to find the distance from the launch point a projectile is when it reaches its maximum height.
We can use the equation
to find the maximum height
When the particle is at its maximum height, the instantaneous velocity
The initial
Plugging in known values, we have
To find the horizontal distance covered
The time
Rearranging this equation and plugging in known values:
Thus, we have
The distance from the starting point is thus
THe distance is
Explanation:
Resolving in the vertical direction
initial velocity is
Acceleration is
At the maximum height,
We apply the equation of motion
to calculate the time to reach the greatest height
The greatest height is
Resolving in the horizontal direction
To find the horizontal distance, we apply the equation of motion
The distance from the starting point is