A projectile is shot from the ground at an angle of #pi/6 # and a speed of #25 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?
1 Answer
Explanation:
The velocity of projection of the projectile
The angle of projection of the projectile
The horizontal component of velocity of projection
TheVertical component of velocity of projection
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Assuming the ideal situation where gravitational pull is the only force acting on the body and no air resistance exists , we can easily proceed for various calculation using equation of motion under gravity.
CALCULATION
Let the projectile reaches its maximum height H m after t s of its start.
The final vertical component of its velocity at maximum height will be zero
So we can write
Again
During
Hence the projectil's distance ( D ) from starting point to the maximum point of its ascent is given by
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