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A rectangle with perimeter 104 cm has a width of 18 cm less that its length. What is the area?

1 Answer

Feb 22, 2016

Area $= 595 c m^{2}$ $=595 cm^2$

Explanation:

Let the length of the rectangle be $= l$ $=l$
Then its width $= l - 18$ $=l-18$

Its perimeter is $= 104 c m$ $=104 cm$

2(width + length) $= 104$ $=104$

$2 ((l - 18) + l) = 104$ $2((l-18)+l)=104$
$2 (l - 18 + l) = 104$ $2(l-18+l)=104$
$2 l - 36 + 2 l = 104$ $2l-36+2l=104$
$4 l = 104 + 36$ $4l=104+36$
$l = \frac{140}{4} = 35$ $l=140/4=35$
$w = 35 - 18 = 17$ $w=35-18=17$
Area $= w \times l = 17 \times 35 = 595 c m^{2}$ $= w xx l=17xx 35=595 cm^2$

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